C# Code Snippets

Distance Calculation using
Latitude and Longitude in C#

ZIPCodeWorld

ZIPCodeWorld.com provides this routine to calculate the distance between two points (given the latitude/longitude of those points) in C#. It is being used to calculate distance between two points lat1, long1 and lat2, long2 and uses radius of earth in kilometers or miles as an argurments using our ZIPCodeWorld(TM) and PostalCodeWorld(TM) products which offer the United States ZIP codes, Canadian Postal Codes, Mexican Postal Codes and North American Area Codes database subscription and solution services.

Platform: .NET Framework 2.0

using System;

private double distance(double lat1, double lon1, double lat2, double lon2, char unit) {
  double theta = lon1 - lon2;
  double dist = Math.Sin(deg2rad(lat1)) * Math.Sin(deg2rad(lat2)) + 
                Math.Cos(deg2rad(lat1)) * Math.Cos(deg2rad(lat2)) * 
                Math.Cos(deg2rad(theta));
  dist = Math.Acos(dist);
  dist = rad2deg(dist);
  dist = dist * 60 * 1.1515;
  if (unit == 'K') {
    dist = dist * 1.609344;
  } else if (unit == 'N') {
  	dist = dist * 0.8684;
  }
  return (dist);
}

//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
//::  This function converts decimal degrees to radians             :::
//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
private double deg2rad(double deg) {
  return (deg * Math.PI / 180.0);
}

//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
//::  This function converts radians to decimal degrees             :::
//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
private double rad2deg(double rad) {
  return (rad / Math.PI * 180.0);
}

Console.WriteLine(distance(32.9697, -96.80322, 29.46786, -98.53506, "M"));
Console.WriteLine(distance(32.9697, -96.80322, 29.46786, -98.53506, "K"));
Console.WriteLine(distance(32.9697, -96.80322, 29.46786, -98.53506, "N"));

 

 

Back to C# Code Snippet List

Other C# Articles
Unable to connect to database! Please try again later.